document.write( "Question 1028653: The length of a rectangle is 3 yards less than the twice the width, and the area of the rectangle is 27 yards to the power of two. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #643984 by Theo(13342)\"\" \"About 
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x equals the length
\n" ); document.write( "y equals the width
\n" ); document.write( "the length is 3 yards less than twice the width.
\n" ); document.write( "x = 2y-3
\n" ); document.write( "area is 27^2
\n" ); document.write( "length * width = area.
\n" ); document.write( "x*y = 27^2
\n" ); document.write( "since x = 2y-3, the formula becomes (2y-3)*y = 27^2
\n" ); document.write( "simplify to get 2y^2 - 3y = 729
\n" ); document.write( "subtract 27^2 from both sides of the equation to get 2y^2 - 3y - 729 = 0
\n" ); document.write( "use the quadratic formula to get:
\n" ); document.write( "y = 19.856608804285 or y = -18.something.
\n" ); document.write( "y can't be negative, so it has to be 19.8566.....
\n" ); document.write( "x = 2y-3, so x = 36.71321761
\n" ); document.write( "the area of the rectangle is x*y = 19.856608804285 * 36.71321761 = 729.
\n" ); document.write( "729 is equal to 27^2, so the requirements of the problem are satisfied.\r
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