document.write( "Question 1028894: Solve the quadratic \"2%28x-2%29%5E2=22\" equation by taking square roots.\r
\n" ); document.write( "\n" ); document.write( "x=
\n" ); document.write( "x=
\n" ); document.write( "

Algebra.Com's Answer #643981 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
start with:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2 * (x-2)^2 = 22\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 2 to get (x-2)^2 = 11\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "take the square root of both sides of the equation to get x-2 = plus or minus sqrt(11).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "add 2 to both sides of the equation to get x = 2 plus or minus sqrt(11)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "you have two possible values for x.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = 2 + sqrt(11)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = 2 - sqrt(11)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "replace x in the original equation with these values and you'll see that the equation is true.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );