document.write( "Question 1028760: A rectangular box is to have a square base and a volume of 40 ft3. If the material for the base costs $0.35/ft2, the material for the sides costs $0.05/ft2, and the material for the top costs $0.15/ft2, determine the dimensions of the box that can be constructed at minimum cost.
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Algebra.Com's Answer #643973 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A rectangular box is to have a square base and a volume of 40 ft3. \n" ); document.write( " If the material for the base costs $0.35/ft2, the material for the sides costs $0.05/ft2, and the material for the top costs $0.15/ft2, determine the dimensions of the box that can be constructed at minimum cost. \n" ); document.write( ": \n" ); document.write( "let x = the length of the side of the square base \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Area of the top and bottom will be x^2 \n" ); document.write( "Area of each of the 4 sides will be : \n" ); document.write( " \n" ); document.write( "Fours sides area: 4* \n" ); document.write( ": \n" ); document.write( "The cost equation \n" ); document.write( "Cost = base cost + side cost + top cost \n" ); document.write( "C(x) = \n" ); document.write( "C(x) = \n" ); document.write( "Graph this equation to find the min cost \n" ); document.write( " \n" ); document.write( "minimum cots occurs when x = 1.7 ft, the length and width of the box \n" ); document.write( "Find the height \n" ); document.write( "h = \n" ); document.write( "h = 13.8 ft \n" ); document.write( ": \n" ); document.write( "The box dimension for min cost: 1.7 by 1.7 by 13.8 \n" ); document.write( " |