document.write( "Question 1028760: A rectangular box is to have a square base and a volume of 40 ft3. If the material for the base costs $0.35/ft2, the material for the sides costs $0.05/ft2, and the material for the top costs $0.15/ft2, determine the dimensions of the box that can be constructed at minimum cost.
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Algebra.Com's Answer #643973 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular box is to have a square base and a volume of 40 ft3.
\n" ); document.write( " If the material for the base costs $0.35/ft2, the material for the sides costs $0.05/ft2, and the material for the top costs $0.15/ft2, determine the dimensions of the box that can be constructed at minimum cost.
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\n" ); document.write( "let x = the length of the side of the square base
\n" ); document.write( "then
\n" ); document.write( "\"40%2Fx%5E2\" = the height of the box
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\n" ); document.write( "Area of the top and bottom will be x^2
\n" ); document.write( "Area of each of the 4 sides will be :
\n" ); document.write( "\"x%2840%2Fx%5E2%29\" simplifies to \"40%2Fx\"
\n" ); document.write( "Fours sides area: 4*\"40%2Fx\" = \"160%2Fx\"
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\n" ); document.write( "The cost equation
\n" ); document.write( "Cost = base cost + side cost + top cost
\n" ); document.write( "C(x) = \".35x%5E2+%2B+.05%28160%2Fx%29+%2B+.15x%5E2\"
\n" ); document.write( "C(x) = \".50x%5E2+%2B+8%2Fx\"
\n" ); document.write( "Graph this equation to find the min cost
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-2%2C+5%2C+-4%2C+20%2C+.5x%5E2%2B%288%2Fx%29%29+\"
\n" ); document.write( "minimum cots occurs when x = 1.7 ft, the length and width of the box
\n" ); document.write( "Find the height
\n" ); document.write( "h = \"40%2F1.7%5E2\"
\n" ); document.write( "h = 13.8 ft
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\n" ); document.write( "The box dimension for min cost: 1.7 by 1.7 by 13.8
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