document.write( "Question 1028846: A certain furniture store found that 20% of the people who enter buy something. Three potential customers walk in. Y means a sale, and N means no sale.\r
\n" ); document.write( "\n" ); document.write( "1. The most likely outcome is?
\n" ); document.write( " A) YYY B)NNN C)YNY D) NNY E) YNN
\n" ); document.write( "I was thinking it might either be NNN or NNY because the percent is so low. Am I right?\r
\n" ); document.write( "\n" ); document.write( "2. The probability of NNY is?
\n" ); document.write( " A) .128 B) .6 C) .2 D) .5
\n" ); document.write( "How would you solve this?\r
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\n" ); document.write( "\n" ); document.write( "Thanks in advance!
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Algebra.Com's Answer #643940 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The probability of successes in trials where is the probability of success on any given trial is given by:\r
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\n" ); document.write( "\n" ); document.write( "Where is the number of combinations of things taken at a time and is calculated by \r
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\n" ); document.write( "\n" ); document.write( "So the probability of 3 Yes results would be:\r
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\n" ); document.write( "\n" ); document.write( "The probability of 2 Yes results (which could be YYN, YNY, or NYY), would be:\r
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\n" ); document.write( "\n" ); document.write( "Each of YYN, YNY, or NYY would be 1/3 of the above result.\r
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\n" ); document.write( "\n" ); document.write( "The probability of 1 Yes result (YNN, NYN, or NNY) would be:\r
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\n" ); document.write( "\n" ); document.write( "Each of YNN, NYN, and NNY would be 1/3 of the above, so P(NNY) = 0.128\r
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\n" ); document.write( "\n" ); document.write( "The probability of Zero Yes results, NNN, would be:\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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