document.write( "Question 1028772: Could someone please help me with writing a conic equation in standard form for a hyperbola with vertices at (1,6) and (1,-2) and asymptotes at y=(4/3)x+2/3 and y=(-4/3)x+10/3. I would appreciate any help!!! \n" ); document.write( "
Algebra.Com's Answer #643923 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
The transverse axis should be parallel to the y-axis, and the center is at the point (1,2), the midpoint of the vertices (1,6) and (1,-2).\r
\n" ); document.write( "\n" ); document.write( "The standard form is then given by \"%28y-2%29%5E2%2Fa%5E2+-+%28x-1%29%5E2%2Fb%5E2+=+1\"\r
\n" ); document.write( "\n" ); document.write( "<==> y-2 = +/- \"%28a%2Fb%29sqrt%28b%5E2%2B%28x-1%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "For very large positive/negative x-values, \r
\n" ); document.write( "\n" ); document.write( "y-2 = +/-\"%28a%2Fb%29%28x-1%29%29\". (Suppress \"b%5E2\".
\n" ); document.write( "==> y = +/-\"%28a%2Fb%29%28x-1%29%29\" + 2.\r
\n" ); document.write( "\n" ); document.write( "y = +/-\"%284%2F3%29%28x-1%29%29\" + 2.\r
\n" ); document.write( "\n" ); document.write( "Hence let a = 4 and b = 3, and the standard form is \"%28y-2%29%5E2%2F16+-+%28x-1%29%5E2%2F9+=+1\"
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