document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12654>Question 12654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve this please <BR>\n" );
document.write( "3x+2y-z+8<BR>\n" );
document.write( "-3x+4y+5z=-14<BR>\n" );
document.write( "x-3y+4z=-14\r<BR>\n" );
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document.write( "Use linear combinations AND substitution.\r<BR>\n" );
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document.write( "thanks very you much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6439 by </B><A HREF=/tutors/aboutme.mpl?userid=AdolphousC><B>AdolphousC(70)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AdolphousC><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using your third equation, solve for X and substitute it in for X in your other two equations...<BR><BR>\n" );
document.write( "X = 3y - 4z - 14<BR><BR>\n" );
document.write( "3(3y - 4z - 14) + 2y - z = 8     <BR>\n" );
document.write( "   9y - 12z - 42 + 2y - z = 8       <BR>\n" );
document.write( "   11y - 13z - 42 = 8            <BR>\n" );
document.write( "   11y - 13z = 50 <BR>\n" );
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document.write( "-3(3y - 4z - 14) + 4y + 5z = -14 <BR>\n" );
document.write( "     9y - 12z - 42 + 2y - z = 8  <BR>\n" );
document.write( "    -9y + 12z + 42 + 4y + 5z = -14 <BR>\n" );
document.write( "    -5y + 17z + 42 = -14 <BR>\n" );
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document.write( "Take these two equations and use linear combinations<BR>\r<BR>\n" );
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document.write( "   5(11y - 13z = 50)                    <BR>\n" );
document.write( "  11(-5y + 17z = -56)<BR>\n" );
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document.write( "   55y -  65z = 250<BR>\n" );
document.write( "+ -55y + 187x = -616<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "         122z = -366  ----> <B> ( Z = -3 ) </B><BR>\n" );
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document.write( "Now that we know Z = -3, substitute it back into two of your original equations.<BR>\n" );
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document.write( "3x + 2y - (-3) = 8              <BR>\n" );
document.write( "3x + 2y + 3 = 8                                     <BR>\n" );
document.write( "-3x + 4y = 1<BR>\n" );
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document.write( "-3x + 4y + 5(-3) = -14<BR>\n" );
document.write( "-3x + 4y - 15 = -143x + 2y = 5 <BR>\n" );
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document.write( "Use these to do Linear Combinations<BR>\n" );
document.write( "    3x + 2y = 5<BR>\n" );
document.write( "+  -3x + 4y = 1<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "         6y = 6     ------> <B> ( Y = 1 ) </B><BR>\n" );
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document.write( "Now Take your Original Equation 3x+2y-z=8 Substitute Z and Y to find X<BR>\n" );
document.write( "   3x + 2(1) - (-3) = 8<BR>\n" );
document.write( "   3x + 2 + 3 = 8<BR>\n" );
document.write( "   3x + 5 = 8<BR>\n" );
document.write( "   3x = 3<BR>\n" );
document.write( "    x = 1\r<BR>\n" );
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document.write( "So Z = -3, Y = 1, and X = 1 </SPAN>\n" );
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