document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88528>Question 88528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rewrite the equation given in Problem 18 to be a function of x.  As it turns out, this is very much like Part (b) of Example 4 on p. 656!\r<BR>\n" );
document.write( "\n" );
document.write( "18) -3x + 4y = 11<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64389 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rewrite the equation given in Problem 18 to be a function of x. As it turns out, this is very much like Part (b) of Example 4 on p. 656!<BR>\n" );
document.write( "18) -3x + 4y = 11<BR>\n" );
document.write( ":<BR>\n" );
document.write( "4y = 3x + 11; added 3x to both sides<BR>\n" );
document.write( "y = (3/4)x + (11/4); divided both sides by 4<BR>\n" );
document.write( ":<BR>\n" );
document.write( "y = f(x)<BR>\n" );
document.write( "Therefore:<BR>\n" );
document.write( "f(x) = (3/4)x + (11/4) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );