document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028811>Question 1028811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a meeting of 31 people. How many ways can one choose a team of two people from those attending the meeting? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643860 by </B><A HREF=/tutors/aboutme.mpl?userid=kev82><B>kev82(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kev82><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 31 choices for the first person, there are then 30 choices for the second person. However it's the same pair regardless of the order I choose them in (AB = BA) so that gives 30*31/2 = 15*31 = 465. </SPAN>\n" );
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