document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028603>Question 1028603</A>: <I><SPAN STYLE=\"word-break: break-all;\">   1 mole of carbon-12 contains 6.022*10^23 carbon-12 atoms with a mass of 12g. <BR>\n" );
document.write( " What is the mass of 1 carbon-12 atom using scientific notation?<BR>\n" );
document.write( " What is the mass of carbon-12 atoms in 20.0g of carbon-12?<BR>\n" );
document.write( " Calculate the number of moles of carbon-12 atoms in 20.0g of carbon-12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643827 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643827\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i'm not quite sure what you're asking here.\r<BR>\n" );
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document.write( "you state that 1 mole of carbon 12 has a mass of 12 grams and contains 6.022 * 10^23 atoms of carbon 12.\r<BR>\n" );
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document.write( "this means that 6.022 * 10^23 atoms of carbon 12 has a mass of 12 grams.\r<BR>\n" );
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document.write( "you can solve the the mass of one carbon 12 atom by dividing 12 by 6.022 * 10^23.\r<BR>\n" );
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document.write( "since 12 is equivalent to 12 * 10^0, you would then divide 12 * 10^0 by 6.022 * 10^23 which will result in 12/6.022 * 10^0/10^23 which will then be equal to 1.992693457 * 10^-23 grams.\r<BR>\n" );
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document.write( "that should answer your first question which was:\r<BR>\n" );
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document.write( "what is the mass of 1 carbon 12 atom.\r<BR>\n" );
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document.write( "the solution is that one carbon 12 atom has a mass of 1.992693457 * 10^-23 grams.\r<BR>\n" );
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document.write( "your second question was:\r<BR>\n" );
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document.write( "What is the mass of carbon-12 atoms in 20.0g of carbon-12?\r<BR>\n" );
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document.write( "the solution to that should be 20 grams.\r<BR>\n" );
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document.write( "you might have asked how many atoms of carbon 12 in 20 grams of carbon 12.\r<BR>\n" );
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document.write( "that would then be 20/12 * 6.022 * 10^23 = 10.03666667 * 10^23 atoms.\r<BR>\n" );
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document.write( "if you multiply that by the mass per gram of carbon 12, you should get 20.\r<BR>\n" );
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document.write( "i did and i got 20 grams, as i should have.\r<BR>\n" );
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document.write( "your last question asks how many moles are in 20 grams of carbon 12.\r<BR>\n" );
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document.write( "if 1 mole weights 12 grams, then take 20 and divide it by 12 and you will get 20/12 = 1.6666666666.... moles, which is equal to 1 and 2/3 moles.\r<BR>\n" );
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document.write( "i think this is right.<BR>\n" );
document.write( "check it out and get back to me if you don't agree, or if the solutions that you're supposed to get don't agree.\r<BR>\n" );
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