document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028747>Question 1028747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I hav used the quadratic formular to find the x-intercepts of y=x^2+2x-5<BR>\n" );
document.write( "to be left with x=-1-sqrt(6) and x=-1+sqrt(6)<BR>\n" );
document.write( "and now need to find the distance between them which is the part I'm stuck on. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643819 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I hav used the quadratic formular to find the x-intercepts of y=x^2+2x-5<BR>\n" );
document.write( "to be left with x=-1-sqrt(6) and x=-1+sqrt(6)<BR>\n" );
document.write( "and now need to find the distance between them which is the part I'm stuck on.<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "Since they're both on the x-axis, it's<BR>\n" );
document.write( "-1+sqrt(6) - (-1-sqrt(6))<BR>\n" );
document.write( "= 2sqrt(6)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );