document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028727>Question 1028727</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Can you help me solve this?                                                   1 mole of carbon-12 contains 6.022*10^23 carbon-12 atoms. with a mass of 12g.\r<BR>\n" );
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document.write( " Calculate the mass of 1 carbon-12 atom with scientific notation.<BR>\n" );
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document.write( " Calculate the mass of carbon-12 atoms in 20.0g of carbon-12.\r<BR>\n" );
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document.write( " Calculate the number of moles of  carbon-12 atoms in  20.0g of carbon-12<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643806 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "the mass of 1 carbon-12 atom with scientific notation\r<BR>\n" );
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document.write( "12/6.022 x 10^23 and get 1.99*10^23\r<BR>\n" );
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document.write( "the mass of carbon-12 atoms in 20.0g of carbon-12.\r<BR>\n" );
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document.write( "12g contain 6.022 x 10^23 \r<BR>\n" );
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document.write( "20 g will contain (20/12) 6.022*10^23\r<BR>\n" );
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document.write( "7.527 * 10^23 </SPAN>\n" );
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