document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028654>Question 1028654</A>: <I><SPAN STYLE=\"word-break: break-all;\">  The sum of two numbers is 400. If the first number were decreased by 20% and the second number were decreased by 15%, then the sum would be 68 less. Find the numbers after decreasing. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643778 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x and 400 - x be the two numbers.\r<BR>\n" );
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document.write( "==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.\r<BR>\n" );
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document.write( "<==> 0.80x + 0.85(400 - x) = 400 - 68\r<BR>\n" );
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document.write( "==> 340 - 0.05x = 332\r<BR>\n" );
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document.write( "<==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.\r<BR>\n" );
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