document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028691>Question 1028691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A tour bus in Boston serves 400 customers a day. The charge is $5 per person. Suppose that for each $0.50 increase in fare, a bus company will lose 8 passengers. Determine how much the fare should be in order to maximize the income, and then determine the maximum income. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643774 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Income = (5 + 0.50x)(400 - 8x), where x = number of increment times.\r<BR>\n" );
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document.write( "==> Income = 4(10 + x)(50 - x), after factoring.\r<BR>\n" );
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document.write( "==> The roots are x = -10, 50.<BR>\n" );
document.write( "The maximum is attained at the midpoint of -10 and 50, namely x = 20.\r<BR>\n" );
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document.write( "==> The fare should be $15 in order to maximize income, and the maximum income is $3,600. </SPAN>\n" );
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