document.write( "Question 1028660: Suppose that the weight of cereal in boxes is labeled to have 20 oz is distributed with mean 20.1 oz and standard deviation .2 oz. Let Y be the weight of the cereal in a random box. A consumer buys a box of cereal and the weight is 19.7 oz. What is the probability that the weight of cereal is 19.7 oz or less, that is calculate P(Y<19.7)
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Algebra.Com's Answer #643766 by rothauserc(4718)\"\" \"About 
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Use normal distribution
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\n" ); document.write( "Calculate the z-value
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\n" ); document.write( "z-value = (Y - mean) / standard deviation
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\n" ); document.write( "z-value = (19.7 - 20.1) / .2 = -2
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\n" ); document.write( "Consult table of z-values to find probability
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\n" ); document.write( "P ( Y < 19.7 ) = 0.0228
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