document.write( "Question 1028660: Suppose that the weight of cereal in boxes is labeled to have 20 oz is distributed with mean 20.1 oz and standard deviation .2 oz. Let Y be the weight of the cereal in a random box. A consumer buys a box of cereal and the weight is 19.7 oz. What is the probability that the weight of cereal is 19.7 oz or less, that is calculate P(Y<19.7)
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document.write( "I am having trouble finding P. Thanks! \n" );
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Algebra.Com's Answer #643766 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! Use normal distribution \n" ); document.write( ": \n" ); document.write( "Calculate the z-value \n" ); document.write( ": \n" ); document.write( "z-value = (Y - mean) / standard deviation \n" ); document.write( ": \n" ); document.write( "z-value = (19.7 - 20.1) / .2 = -2 \n" ); document.write( ": \n" ); document.write( "Consult table of z-values to find probability \n" ); document.write( ": \n" ); document.write( "P ( Y < 19.7 ) = 0.0228 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |