document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028675>Question 1028675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value(s) of k that makes the second polynomial a factor of the first. (Enter your answers as a comma-separated list.)\r<BR>\n" );
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document.write( "kx^3+20x^2+x-15; x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643748 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643748\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find the value(s) of k that makes the second polynomial a factor of the first. (Enter your answers as a comma-separated list.) <BR>\n" );
document.write( "kx^3+20x^2+x-15; x+3 <BR>\n" );
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document.write( "Use synthetic division::<BR>\n" );
document.write( "-3)....k....20....1....-15<BR>\n" );
document.write( ".......k....20-3k..21-3k..|6-3k<BR>\n" );
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document.write( "Solve:: 6-3k = 0<BR>\n" );
document.write( "k = 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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