document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028643>Question 1028643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of teachers at a local high school is 360 less than one-third of the number of students. If the total number of students and teachers at the school is 1200, how many of them are (a) teachers and (b) students?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643731 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of students and teachers, s and t.  Then we write<BR>\n" );
document.write( "t = (1/3)s - 360  and<BR>\n" );
document.write( "t + s = 1200   (or t = 1200 - s)<BR>\n" );
document.write( "Now substitute and get<BR>\n" );
document.write( "1200 - s = (1/3)s - 360<BR>\n" );
document.write( "Add 360 and add s to both sides...<BR>\n" );
document.write( "1560 = (4/3)s<BR>\n" );
document.write( "Now multiply by 3/4 and get<BR>\n" );
document.write( "s = (3/4)(1560) = 1170 students  <BR>\n" );
document.write( "which means there are<BR>\n" );
document.write( "t = 30 teachers<BR>\n" );
document.write( "(Not a healthy ratio...) </SPAN>\n" );
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