document.write( "Question 1028629: The power (in Watts) from an engine is represented by the equation : P = 100t^1.4 + 6t , where t is the time.?
\n" ); document.write( "in Seconds. \r
\n" ); document.write( "\n" ); document.write( "1: Draw the graph that represents power against time for this engine. \r
\n" ); document.write( "\n" ); document.write( "2.show the area on the graph which represents the energy converted between 5s and 15s \r
\n" ); document.write( "\n" ); document.write( "3. show, using summation how you would gain an approximation for the energy \r
\n" ); document.write( "\n" ); document.write( "4. using intergration, evaluate the exact energy between 5s and 15s
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Algebra.Com's Answer #643720 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
1. .
\n" ); document.write( "2. Area of the trapezoid marked by the black dashed boundaries and the graph.
\n" ); document.write( "3. You could just calculate the area of the trapezoid or using a \"dx\", make a summation.
\n" ); document.write( "\"A=sum%28P%28x%29%2Adx%2Cx=1%2CN%29\"
\n" ); document.write( "4. \"int%28P%28t%29%2Cdt%2C5%2C15%29=100%28t%5E%281.4%2B1%29%29%2F%282.4%29%2B3t%5E2%2BC\"
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\n" ); document.write( "\"int%28P%28t%29%2Cdt%2C5%2C15%29=%28125%2F3%29%28664.69-47.59%29%2B3%28225-25%29\"
\n" ); document.write( "\"int%28P%28t%29%2Cdt%2C5%2C15%29=%28125%2F3%29%28617.1%29%2B3%28200%29\"
\n" ); document.write( "\"int%28P%28t%29%2Cdt%2C5%2C15%29=25712.5%2B600\"
\n" ); document.write( "\"int%28P%28t%29%2Cdt%2C5%2C15%29=26312.5\"\"Watt-s\"or \"J\"
\n" ); document.write( "As a comparison, the area of the trapezoid would yield,
\n" ); document.write( "\"A=%281%2F2%29%2810%29%284431.265%2B951.827%29\"
\n" ); document.write( "\"A=27515.5\"
\n" ); document.write( "Also, a summation using \"dx=0.5\" would yield,
\n" ); document.write( "\"A=27061.3\"
\n" ); document.write( "Even closer.
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