document.write( "Question 88513: The length of a rectangle is 5in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #64358 by checkley75(3666)\"\" \"About 
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LENGTH=(2W+5)
\n" ); document.write( "2L+2W=52
\n" ); document.write( "2(2W+5)+2W=52
\n" ); document.write( "4W+10+2W=52
\n" ); document.write( "6W=52-10
\n" ); document.write( "6W=42
\n" ); document.write( "W=42/6
\n" ); document.write( "W=7 INCHES IS THE WIDTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2(2*7+5)+2*7=52
\n" ); document.write( "2(14+5)+14=52
\n" ); document.write( "2*19+14=52
\n" ); document.write( "38+14=52
\n" ); document.write( "52=52
\n" ); document.write( "
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