document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991826>Question 991826</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is two less than a second number. Six times the first is 3 more than 3 times the second </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643572 by </B><A HREF=/tutors/aboutme.mpl?userid=EdenWolf><B>EdenWolf(517)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=EdenWolf><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=EdenWolf><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the second number and (x-2) = the first number. \r<BR>\n" );
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document.write( "6(x-2)=3+3x<BR>\n" );
document.write( "6x-12=3+3x<BR>\n" );
document.write( "Subtract 3x from both sides<BR>\n" );
document.write( "3x-12=3<BR>\n" );
document.write( "Add 12 to both sides<BR>\n" );
document.write( "3x=15<BR>\n" );
document.write( "x=5\r<BR>\n" );
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document.write( "First number: 3<BR>\n" );
document.write( "Second number: 5 </SPAN>\n" );
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