document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028474>Question 1028474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the logarithmic equation algebraically.<BR>\n" );
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document.write( "e^x + e^-x = 4\r<BR>\n" );
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document.write( "please explain how you do this in detail. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643568 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve the logarithmic equation algebraically.<BR>\n" );
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document.write( "e^x + e^-x = 4<BR>\n" );
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document.write( "Multiply thru by e^2<BR>\n" );
document.write( "e^(2x) + 1 = 4e^x<BR>\n" );
document.write( "e^(2x) - 4e^x + 1 = 0<BR>\n" );
document.write( "Now it's quadratic in e^x.<BR>\n" );
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document.write( "Or,<BR>\n" );
document.write( "e^x + e^-x = 4<BR>\n" );
document.write( "(e^x + e^-x)/2 = 2<BR>\n" );
document.write( "sinh(x) = 2<BR>\n" );
document.write( "x =~ 1.443635 </SPAN>\n" );
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