document.write( "Question 88508: I have been trying to figure out how this is set up but I am confused. So far I not sure if this is the right set up: n-4=96\r
\n" ); document.write( "\n" ); document.write( "Word Problem:
\n" ); document.write( "The product of a number and 4 less than the number is 96. Find the number.
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Algebra.Com's Answer #64356 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=the number
\n" ); document.write( "4 less than the number is x-4\r
\n" ); document.write( "\n" ); document.write( "the product of the number and 4 less than the number is x(x-4) and we are told that this equals 96, so---\r
\n" ); document.write( "\n" ); document.write( "x(x-4)=96 get rid of parens\r
\n" ); document.write( "\n" ); document.write( "x^2-4x=96 subtract 96 from both sides\r
\n" ); document.write( "\n" ); document.write( "x^2-4x-96=0 quadratic in standard form and it has factors\r
\n" ); document.write( "\n" ); document.write( "(x-12)(x+8)=0\r
\n" ); document.write( "\n" ); document.write( "x=12
\n" ); document.write( "and
\n" ); document.write( "x=-8
\n" ); document.write( "CK for x=12\r
\n" ); document.write( "\n" ); document.write( "12(12-4)=96\r
\n" ); document.write( "\n" ); document.write( "12*8=96
\n" ); document.write( "96=96-----------ok\r
\n" ); document.write( "\n" ); document.write( "Ck for x=-8\r
\n" ); document.write( "\n" ); document.write( "-8(-8-4)=96\r
\n" ); document.write( "\n" ); document.write( "(-8)(-12)=96\r
\n" ); document.write( "\n" ); document.write( "96=96\r
\n" ); document.write( "\n" ); document.write( "So both values for x satisfy the problem\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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