document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028461>Question 1028461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sector of a circle of radius 8cm subtends an angle 90 degrees at the centre of the circle. If the sector is folded without overlap to form the curved surface of a cone, find the base radius, height and volume of the cone taking pie as 22/7<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643558 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A sector of a circle of radius 8cm subtends an angle 90 degrees at the centre of the circle. If the sector is folded without overlap to form the curved surface of a cone, find the base radius, height and volume of the cone taking pie as 22/7<BR>\n" );
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document.write( "Perimeter of the circle 16pi <BR>\n" );
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document.write( "Perimeter of the base of the cone:: (3/4)16pi = 12pi<BR>\n" );
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document.write( "height of cone::<BR>\n" );
document.write( "radius of base of cone:: 12pi/(2pi) = 6 <BR>\n" );
document.write( "h^2 = 8^2 - 6^2 = 64-36 = 28<BR>\n" );
document.write( "h = sqrt(28)<BR>\n" );
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document.write( "volume of cone:: (1/3)pi*r^2*h = (1/3)pi*36*<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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