document.write( "Question 1028439: ) Pipestone, Marshall, and Worthington are three cities. Pipestone is 36 miles west of Marshall,
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document.write( "and Worthington is 77 miles north of Marshall. Bert and Tre leave Pipestone at the same time.
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document.write( "Bert goes straight to Worthington at a speed of 25 miles per hour. Tre goes from Pipestone to
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document.write( "Marshall to Worthington at a speed of 35 miles per hour. Who will get to Worthington first?
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document.write( "How much longer will it take for the second person to arrive? Round to the nearest tenth of an
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document.write( "hour \n" );
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Algebra.Com's Answer #643528 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Consider your problem as \n" ); document.write( "a right angled triangle. \n" ); document.write( "Pipestone to Marshall is the base \n" ); document.write( "Marshall to Worthington is the height. \n" ); document.write( "Pipestone to Worthington is the hypotenuse. \n" ); document.write( "Base = 36 miles \n" ); document.write( "Height = 77 miles \n" ); document.write( "Using Pythagoras Theorem \n" ); document.write( "Hypotenuse = 85 miles. \n" ); document.write( "Bert travelled directly to Worthington \n" ); document.write( "at 25 mph. A distance of 85 miles \n" ); document.write( "Time = Distance/Speed \n" ); document.write( "Time = 85/25 \n" ); document.write( "Time = 3.4 hours \n" ); document.write( "Tre travelled first to Marshall and \n" ); document.write( "then to Worthington at 35 mph. A distance \n" ); document.write( "of 36 + 77 = 113 miles \n" ); document.write( "Time = Distance/Speed \n" ); document.write( "Time = 113/35 \n" ); document.write( "Time = 3.2 hours \n" ); document.write( "Tre will arrive first at Worthington \n" ); document.write( "Bert will arrive 0.2 hours later. \n" ); document.write( "0.2 hours = 12 minutes. \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |