document.write( "Question 88509: I havea Question that is really giving me a hard time. Please Help.
\n" ); document.write( "Finf the length of each side of the rectangle so that it has a perimeter of 50. One side is 2x-5 and one side is x.
\n" ); document.write( "

Algebra.Com's Answer #64352 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Start with the formula for the perimeter of a rectangle:
\n" ); document.write( "\"P+=+2L%2B2W\" where, L = length, W = width, and P = 50.
\n" ); document.write( "You are given that one side (let this side be L) is 2x-5 and the other side (let this side be W) is x. Substitute these for L and W into the formula and solve for x.
\n" ); document.write( "\"50+=+2%282x-5%29%2B2x\"
\n" ); document.write( "\"50+=+4x-10%2B2x\"
\n" ); document.write( "\"50+=+6x-10\" Add 10 to both sides.
\n" ); document.write( "\"60+=+6x\" Divide both sides by 6.
\n" ); document.write( "\"10+=+x\"
\n" ); document.write( "So the lengths of the sides of the rectangle are:
\n" ); document.write( "Length = 2x-5 = 2(10)-5 = 20-5 = 15
\n" ); document.write( "Width = x = 10
\n" ); document.write( "
\n" );