document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028409>Question 1028409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jeweler has 30 oz of an alloy consisting of 60 percent gold and 40 percent silver. How much of a second alloy containing 80 percent gold and 20 percent silver must be mixed with the first alloy to obtain an alloy containing 75 percent gold and 25 percent silver? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643508 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A jeweler has 30 oz of an alloy consisting of 60 percent gold and 40 percent silver. How much of a second alloy containing 80 percent gold and 20 percent silver must be mixed with the first alloy to obtain an alloy containing 75 percent gold and 25 percent silver? <BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "gold + gold = gold<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "0.6*30 + 0.8x = 0.75*(30+x)<BR>\n" );
document.write( "----------------------------------<BR>\n" );
document.write( "60*30 + 80x = 75*30 + 75x<BR>\n" );
document.write( "5x = 15*30<BR>\n" );
document.write( "x = 90 oz (amt. of 80% needed)<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------------  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );