document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028287>Question 1028287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sara is 37 years older than Tom. In 10 years, Sara will be double the age of Tom. How old is Tom? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643491 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643491\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their ages now, s and t.  Then we write<BR>\n" );
document.write( "s = t + 37<BR>\n" );
document.write( "In ten years,<BR>\n" );
document.write( "s + 10 = 2(t + 10)<BR>\n" );
document.write( "Now substitute the first equation into the second and get<BR>\n" );
document.write( "t+37 + 10 = 2(t + 10)<BR>\n" );
document.write( "t + 47 = 2t + 20<BR>\n" );
document.write( "Now subtract t and subtract 20 and get<BR>\n" );
document.write( "47 = t + 20<BR>\n" );
document.write( "t = 27 years old (Tom)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );