document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028397>Question 1028397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary if their sum is&#8203; 180°. The larger angle measures <BR>\n" );
document.write( "thirty <BR>\n" );
document.write( "degrees more than <BR>\n" );
document.write( "twice <BR>\n" );
document.write( "the measure of a smaller angle. If x represents the measure of the smaller angle and these two angles are supplementary, find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643478 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643478\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> larger angle:y<BR>\n" );
document.write( "y = 2x+30<BR>\n" );
document.write( "and<BR>\n" );
document.write( "y+x = 180 now substitute for y:<BR>\n" );
document.write( "2x+30+x = 180<BR>\n" );
document.write( "3x = 150<BR>\n" );
document.write( "x = 50 is the small angle, and the large angle is:<BR>\n" );
document.write( "(50*2)+30 = 130<BR>\n" );
document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "50+130 = 180 Correct. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );