document.write( "Question 1028380: After 4 years of investment you earned $252.00 in simple interest. The annual rate of interest was 5.25%. How much wes your initial investment (principal)? \n" ); document.write( "
Algebra.Com's Answer #643473 by Theo(13342)\"\" \"About 
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simple intrest assumes no compounding.\r
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\n" ); document.write( "\n" ); document.write( "the formula is i = p * r * n\r
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\n" ); document.write( "\n" ); document.write( "i = interest
\n" ); document.write( "p is the principal
\n" ); document.write( "r is the interest rate per time period.
\n" ); document.write( "n is the number of time periods.\r
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\n" ); document.write( "\n" ); document.write( "your annual intrest rate is 5.25% = .0525.
\n" ); document.write( "your number of years is 4.
\n" ); document.write( "your interest is 252.\r
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\n" ); document.write( "\n" ); document.write( "the formula becomes 252 = p * .0525 * 4 \r
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\n" ); document.write( "\n" ); document.write( "divide both sidesof this equation by (.0525 * 4) and you get:\r
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\n" ); document.write( "\n" ); document.write( "252 / (.0525 * 3) = p\r
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\n" ); document.write( "\n" ); document.write( "solve for p to get p = 1200.\r
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\n" ); document.write( "\n" ); document.write( "you invested 1200 at .0525 interest rate per year for 4 years.\r
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\n" ); document.write( "\n" ); document.write( ".0525 * 1200 = 63 * 4 = 252.\r
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\n" ); document.write( "\n" ); document.write( "solution looks good.\r
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\n" ); document.write( "\n" ); document.write( "original investment is 1200.\r
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