document.write( "Question 1028380: After 4 years of investment you earned $252.00 in simple interest. The annual rate of interest was 5.25%. How much wes your initial investment (principal)? \n" ); document.write( "
Algebra.Com's Answer #643473 by Theo(13342)![]() ![]() You can put this solution on YOUR website! simple intrest assumes no compounding.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula is i = p * r * n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i = interest \n" ); document.write( "p is the principal \n" ); document.write( "r is the interest rate per time period. \n" ); document.write( "n is the number of time periods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your annual intrest rate is 5.25% = .0525. \n" ); document.write( "your number of years is 4. \n" ); document.write( "your interest is 252.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula becomes 252 = p * .0525 * 4 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sidesof this equation by (.0525 * 4) and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "252 / (.0525 * 3) = p\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for p to get p = 1200.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you invested 1200 at .0525 interest rate per year for 4 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".0525 * 1200 = 63 * 4 = 252.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solution looks good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "original investment is 1200.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |