document.write( "Question 1028382: In a family there are 3 brothers, each 2 years apart in age.
\n" ); document.write( "Their ages total 42.
\n" ); document.write( "Form an equation and solve it to find the age of each child.
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Algebra.Com's Answer #643469 by mananth(16946)\"\" \"About 
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\n" ); document.write( "youngest brother's age be x\r
\n" ); document.write( "\n" ); document.write( "the brothers ages will be \r
\n" ); document.write( "\n" ); document.write( "x,(x+2), (x+2+2)\r
\n" ); document.write( "\n" ); document.write( "x+x+2+x+4=42\r
\n" ); document.write( "\n" ); document.write( "3x+6 =42\r
\n" ); document.write( "\n" ); document.write( "3x = 36\r
\n" ); document.write( "\n" ); document.write( "x=12\r
\n" ); document.write( "\n" ); document.write( "12,14,16 are their ages
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