document.write( "Question 1028284: Bob invested 10000, split into two accounts. The savings account paid 4% annually and the checking account paid 1% annually, and Bob received a total of 358. in interest from the two accounts. How much did Bob put into each account? \n" ); document.write( "
Algebra.Com's Answer #643466 by mananth(16946)\"\" \"About 
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Part I 1.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 4.00% per annum ------------ Amount invested = y =
\n" ); document.write( " 10000
\n" ); document.write( "Interest----- 358
\n" ); document.write( "
\n" ); document.write( "Part I 1.00% per annum ---x
\n" ); document.write( "Part II 4.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 10000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "1.00% x + 4.00% y= 358
\n" ); document.write( "Multiply by 100
\n" ); document.write( "1 x + 4 y= 35800.00 --------2
\n" ); document.write( "Multiply (1) by -1
\n" ); document.write( "we get
\n" ); document.write( "-1 x -1 y= -10000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 3 y= 25800
\n" ); document.write( "divide by 3
\n" ); document.write( " y = 8600
\n" ); document.write( "Part I 1.00% $ 1400
\n" ); document.write( "Part II 4.00% $ 8600
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "1400 --------- 1.00% ------- 14.00
\n" ); document.write( "8600 ------------- 4.00% ------- 344.00
\n" ); document.write( "Total -------------------- 358.00
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\n" ); document.write( "m.ananth@hotmail.ca
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