document.write( "Question 1028377: Solve by elimination method:
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document.write( "(5/2) x + (10/3)y = 55 and (7/3)x + (7/2)y = 56
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document.write( "I know these two equations then equal:
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document.write( "15x+20y=330 and 14x+21y=336\r
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document.write( "But I don't know what to do from there! And what is elimination method anyway? What's the difference between that and substitution method or are they the same thing and are there any other kinds of methods? \n" );
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Algebra.Com's Answer #643465 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 15x+20y=330 \r \n" ); document.write( "\n" ); document.write( "/5\r \n" ); document.write( "\n" ); document.write( "3x+4y=66\r \n" ); document.write( "\n" ); document.write( "14x+21y=336 \n" ); document.write( "/7 \n" ); document.write( "2x+3y=48\r \n" ); document.write( "\n" ); document.write( "3 x + 4 y = 66 .............1 \n" ); document.write( " \n" ); document.write( "2 x + 3 y = 48 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -3 \n" ); document.write( "Multiply (2) by 4 \n" ); document.write( "-9 x -12 y = -198 \n" ); document.write( "8 x + 12 y = 192 \n" ); document.write( "Add the two equations \n" ); document.write( "-1 x = -6 \n" ); document.write( "/ -1 \n" ); document.write( "x = 6 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "3 x + 4 y = 66 \n" ); document.write( "18 + 4 y = 66 \n" ); document.write( " 4 y = 66 -18.00 \n" ); document.write( " 4 y = 48 \n" ); document.write( " y = 12 \n" ); document.write( "x= 6 \n" ); document.write( "y= 12 \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |