document.write( "Question 1028268: Write the standard form of the quadratic function that has the indicated vertex and whose graph passes through the given point. Use a graphing utility to verify your result.\r
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Algebra.Com's Answer #643452 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The answer depends on what you mean by standard form. Some people call standard form and vertex form. And some people refer to as standard form.\r
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\n" ); document.write( "\n" ); document.write( "Either way there are two ways to go about this.\r
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\n" ); document.write( "\n" ); document.write( "Since you are given the vertex and one other point, you can find a third point on the graph by considering symmetry. Since the point (-4,1) is two units to the right of the axis of symmetry, then the function value two units to the left of the axis must be the same, hence the point (-8,1) must also be on the graph.\r
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\n" ); document.write( "\n" ); document.write( "Assuming as standard form, if (-4,1) is on the graph, then it must be true that:\r
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\n" ); document.write( "\n" ); document.write( "Likewise, considering the other two points,\r
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\n" ); document.write( "\n" ); document.write( "The solution to the 3X3 system of equations yields the standard form coefficients.\r
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\n" ); document.write( "\n" ); document.write( "I'll leave it to you to verify that , , and .\r
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\n" ); document.write( "\n" ); document.write( "On the other hand, if by standard form you mean what most folks call the vertex form, you can proceed as follows:\r
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\n" ); document.write( "\n" ); document.write( "Substituting the vertex coordinates:\r
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\n" ); document.write( "\n" ); document.write( "Then, since you know that the point is on the graph,\r
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\n" ); document.write( "\n" ); document.write( "And all you need to do is solve for . Any doubt in your mind that the result will be ?\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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