document.write( "Question 1028359: in 28 years, a woman will be twice as old as she will be in two years. How old is she now? \n" ); document.write( "

Algebra.Com's Answer #643434 by ikleyn(52802) $\"\"$ $\"About$

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\n" ); document.write( "in 28 years, a woman will be twice as old as she will be in two years. How old is she now?
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document.write( "W + 28 = 2(W + 2),\r\n" );
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document.write( "W + 28 = 2W + 4,\r\n" );
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document.write( "28 - 4 = 2W - W,\r\n" );
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document.write( "W = 24.\r\n" );
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document.write( "Answer. Woman present age is 24 years.\r\n" );
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document.write( "Check: in two years W + 2 = 26.\r\n" );
document.write( "       in 28 years W + 28 = 24 + 28 = 52.\r\n" );
document.write( "       52 = 2*26.   OK.\r\n" );
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