document.write( "Question 1028351: An investor invested a total amount of $3100.00 in two mutual funds. One mutual fund earned 4% while the other mutual fund earned 2%. If the investors profit was $98.00 how much was invested in each fund?
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Algebra.Com's Answer #643424 by mananth(16946)\"\" \"About 
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Part I 2.00% per annum ------------- Amount invested =x
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\n" ); document.write( "Interest----- 98
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\n" ); document.write( "Part I 2.00% per annum ---x
\n" ); document.write( "Part II 4.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 3100 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "2.00% x + 4.00% y= 98
\n" ); document.write( "Multiply by 100
\n" ); document.write( "2 x + 4 y= 9800.00 --------2
\n" ); document.write( "Multiply (1) by -2
\n" ); document.write( "we get
\n" ); document.write( "-2 x -2 y= -6200.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 2 y= 3600
\n" ); document.write( "divide by 2
\n" ); document.write( " y = 1800
\n" ); document.write( "Part I 2.00% $ 1300
\n" ); document.write( "Part II 4.00% $ 1800
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\n" ); document.write( "CHECK
\n" ); document.write( "1300 --------- 2.00% ------- 26.00
\n" ); document.write( "1800 ------------- 4.00% ------- 72.00
\n" ); document.write( "Total -------------------- 98.00
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\n" ); document.write( "m.ananth@hotmail.ca
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