document.write( "Question 1028313: 1. Find the standard form of the equation of the parabola with a focus at (0, -9) and a directrix y = 9.\r
\n" ); document.write( "\n" ); document.write( "2. Find the vertex, focus, directrix, and focal width of the parabola. \r
\n" ); document.write( "\n" ); document.write( "x^2 = 12y \n" ); document.write( "

Algebra.Com's Answer #643413 by josgarithmetic(39617) $\"\"$ $\"About$

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You can derive the equation for your question #1 using Distance Formula and the given focus and directrix and the written definition of a parabola. The previous referenced videos show how that is done. \r
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\n" ); document.write( "\n" ); document.write( "Your question number 2 is basically in standard form and shows y as a function of x, and since coefficients are positive, this parabola has a vertex minimum and graph is concave upward. The way the equation is shown corresponds to $\"x%5E2=4py\"$ , which can also be expanded to $\"%28x-0%29%5E2=12%28y-0%29\"$ , telling you that vertex is at the origin, and you find p from $\"12=4p\"$ ; and knowing p will give you information to find the focus and the directrix. \n" ); document.write( "

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