document.write( "Question 1028260: When a ball is served, consider the trajectory of ball modelled by equation y=-x^2/8 + 9x/8 +5/4. Find the height of the ball when it is 3m horizontally from where served. (Y represents height of ball in metres above ground and x represents horizontal distance from when ball was struck).\r
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document.write( "I believe 5/4 (y intercept)represents the initial height and that the ball travels 10m (x intercept) but I'm stuck with how to calculate the height after 3 metres.
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document.write( "any help/advice would be great
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document.write( "Thanks \n" );
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Algebra.Com's Answer #643403 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! When a ball is served, consider the trajectory of ball modelled by equation y=-x^2/8 + 9x/8 +5/4. \n" ); document.write( "Find the height of the ball when it is 3m horizontally from where served. \n" ); document.write( " (Y represents height of ball in metres above ground and x represents horizontal distance from when ball was struck). \n" ); document.write( " \n" ); document.write( "find y when x=3 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "y = 3.5 meters is the height \n" ); document.write( " |