document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028258>Question 1028258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a circle is inscribed in a square. write and simplify an expression for the ratio of the area of the square of the area of the circle. for a circle inscribed in a square, the diameter of the circle is equal to the side length of the square?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643376 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the radius of the circle, r.<BR>\n" );
document.write( "Its diameter is 2r.<BR>\n" );
document.write( "The side of the square is then also 2r.<BR>\n" );
document.write( "The area of the circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%28pi%29r%5E2 ALIGN=MIDDLE  ALT=\"A+=+%28pi%29r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "The area of the square is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%282r%29%5E2+=+4r%5E2 ALIGN=MIDDLE  ALT=\"A+=+%282r%29%5E2+=+4r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "The ratio is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4r%5E2+%2F+%28%28pi%29%2Ar%5E2%29+=+4%2F%28pi%29 ALIGN=MIDDLE  ALT=\"4r%5E2+%2F+%28%28pi%29%2Ar%5E2%29+=+4%2F%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );