document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028264>Question 1028264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8x3+125y3+2x-5y\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643371 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can factor the sum of cubes and get<BR>\n" );
document.write( "8x^3 + 125y^3 + 2x - 5y = <BR>\n" );
document.write( "(2x + 5y)(4x^2 - 10xy + 25y^2) + 2x - 5y<BR>\n" );
document.write( "but that is about as far as we can go... </SPAN>\n" );
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