document.write( "Question 1028224: 40 men can complete a work in 40 days. They started the work together But at the end of each day 10th day, 5 men left the job, the work would have completed in
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document.write( "a)56 2/3 days
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document.write( "b)53 1/3 days
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document.write( "c)52 days
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document.write( "d)50 days \n" );
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Algebra.Com's Answer #643359 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Here the job takes 40*40 = 1600 man-days. \n" ); document.write( "After the 10th day, 1/4 of the job was done. 3/4 of the job to go...that would be 1200 man-days. \n" ); document.write( "Five men leaving means there are 35 to finish... \n" ); document.write( "The number of days to finish is \n" ); document.write( "1200/35 = 34 2/7 days \n" ); document.write( "And even if you add the original 10 days, you don't get one of the choices. \n" ); document.write( "Please repost with the correct problem. \n" ); document.write( " |