document.write( "Question 1028184: We were asked to solve logarithmic inequations, and although I could solve it, I stopped at a dead end, in which I couldn't find a ''good'' answer..
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document.write( "i) 2*ln(x+2)-1 > 0
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document.write( "ii) log(3-2x) > 1 + log(x+5)\r
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document.write( "*Sorry if I posted this again* \n" );
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Algebra.Com's Answer #643329 by robertb(5830) You can put this solution on YOUR website! i) \n" ); document.write( "==> \n" ); document.write( "==> \n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "ii) \n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( "==> \n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "The critical numbers are -47/12 and -5. (The numbers that make the numerator and denominator equal to zero.) \n" ); document.write( "Choose test numbers -6, -4, and 0. (Corresponding to the partition ( \n" ); document.write( "Upon substitution into \n" ); document.write( "Therefore the solution is the open interval (-5,-47/12). \n" ); document.write( " |