document.write( "Question 1028184: We were asked to solve logarithmic inequations, and although I could solve it, I stopped at a dead end, in which I couldn't find a ''good'' answer..
\n" ); document.write( "i) 2*ln(x+2)-1 > 0
\n" ); document.write( "ii) log(3-2x) > 1 + log(x+5)\r
\n" ); document.write( "\n" ); document.write( "*Sorry if I posted this again*
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Algebra.Com's Answer #643329 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
i) \"2ln%28x%2B2%29-1+%3E+0+\"
\n" ); document.write( "==> \"ln%28x%2B2%29+%3E+1%2F2\"
\n" ); document.write( "==> \"x%2B2+%3E+e%5E%281%2F2%29+=+sqrt%28e%29\"
\n" ); document.write( "==> \"x+%3E+sqrt%28e%29+-+2\" ≈ -0.35.\r
\n" ); document.write( "\n" ); document.write( "ii) \"log%28%283-2x%29%29+%3E+1+%2B+log%28%28x%2B5%29%29+\"
\n" ); document.write( "==> \"log%28%283-2x%29%2F%28x%2B5%29%29+%3E+1\"\r
\n" ); document.write( "\n" ); document.write( "==> \"%283-2x%29%2F%28x%2B5%29+%3E+10\"
\n" ); document.write( "==> \"%283-2x%29%2F%28x%2B5%29+-+10+%3E0\"
\n" ); document.write( "==> \"%283-2x-10x-50%29%2F%28x%2B5%29%3E0\"\r
\n" ); document.write( "\n" ); document.write( "==> \"%28-12x+-+47%29%2F%28x%2B5%29+%3E+0\"\r
\n" ); document.write( "\n" ); document.write( "The critical numbers are -47/12 and -5. (The numbers that make the numerator and denominator equal to zero.)
\n" ); document.write( "Choose test numbers -6, -4, and 0. (Corresponding to the partition (\"-infinity\",-5), (-5,-47/12), (-47/12, \"infinity\"). )
\n" ); document.write( "Upon substitution into \"%28-12x+-+47%29%2F%28x%2B5%29\", the signs are (-), (+), and (-).
\n" ); document.write( "Therefore the solution is the open interval (-5,-47/12).
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