document.write( "Question 1028182: The excersise goes like that:
\n" ); document.write( "''Solve this logarithmix equation:
\n" ); document.write( "1. 2*log*(2x-1) - log*(3x-2x^2) = log*(4x-3)-log*x \r
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Algebra.Com's Answer #643325 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"log%28%282x-1%29%5E2%29-log%283x-2x%5E2%29=log%28%284x-3%29%2F%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%282x-1%29%5E2%2F%283x-2x%5E2%29%29=log%28%284x-3%29%2Fx%29\"\r
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\n" ); document.write( "\n" ); document.write( "Temporary change in variables saying as \"log%28%28A%29%29=log%28%28B%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"%282x-1%29%5E2%2F%283x-2x%5E2%29=%284x-3%29%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x-1%29%5E2=%283x-2x%5E2%29%284x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%284x%5E2-4x%2B1%29=12x%5E2-9x-8x%5E3%2B6x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E3-4x%5E2%2Bx=18x%5E2-9x-8x%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"12x%5E3-22x%5E2%2B10x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E3-11x%5E2%2B5x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%286x%5E2-11x%2B5%29=0\"
\n" ); document.write( "You are not interested in x=0, because you cannot have log of negative values as would happen in the original equation. Put attention instead on the remaining roots of the quadratic factor.\r
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\n" ); document.write( "\n" ); document.write( "Discrim, \"%28-11%29%5E2-4%2A6%2A5=121-6%2A20=1\"
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\n" ); document.write( "\"x=%2811%2B-+1%29%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28system%28x=5%2F6%2Cor%2Cx=1%29%29\"
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