document.write( "Question 1028017: I'm having a hard time constructing a proof for the following argument.\r
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document.write( "M&~Q
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document.write( "M->S
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document.write( "S->P
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document.write( "And the goal is ~(P->Q) \n" );
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Algebra.Com's Answer #643294 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! M is true, so apply rules 2 and 3:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "M --> S --> P, so P is true \n" ); document.write( "Q is not true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore it is not true that P implies Q. \n" ); document.write( " |