document.write( "Question 1028126: One thousand tickets are sold at $1 each. One ticket will be randomly selected and the winner will receive a
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document.write( "color television valued at $398. What is the expected value for a person that buys one ticket? \n" );
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Algebra.Com's Answer #643290 by mathmate(429) You can put this solution on YOUR website! \n" ); document.write( "Question: \n" ); document.write( "One thousand tickets are sold at $1 each. One ticket will be randomly selected and the winner will receive a \n" ); document.write( "color television valued at $398. What is the expected value for a person that buys one ticket? \n" ); document.write( " \n" ); document.write( "Solution: \n" ); document.write( "Expected value E[x]=μ is the overall average value of the game, defined by \n" ); document.write( "E[x]=∑ x*P(x) where the summation is taken over all outcomes. \n" ); document.write( "x=value of an outcome, \n" ); document.write( "P(x)=probability of that outcome. \n" ); document.write( " \n" ); document.write( "For the given problem, we have 1000 tickets, out of which one will win a television worth 398. That means 999 people will pay $1 (with a probability of 999/1000 losing) , and the winner will get a value of $398-$1=$397 with a probability of 1/1000 winning). \n" ); document.write( "Summing over the whole population, \n" ); document.write( "E[x]=(-1)*999/1000+(397)*1/1000=-602/1000=-0.602 (in dollars) \n" ); document.write( " |