document.write( "Question 1028105: First, Graph: f(x) =x^2+2/x^2+x-2\r
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document.write( "Then:\r
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document.write( "Identify Vertical Asymptotes:\r
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document.write( "Identify Horizontal Asymptotes:\r
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document.write( "Identify Oblique Asymptote:\r
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document.write( "Algebraic verification: \n" );
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Algebra.Com's Answer #643288 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! f(x) =x^2+2/x^2+x-2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The second definition is assumed in this work.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First, here is the graph, simply applying the graphing code for the site: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factorize numerator and denominator completely, at least for Real number purposes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "No hole since no factor is common between numerator and denominator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Undefined for x=1 and x=-2, so this causes vertical asymptotes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Degree of numerator and denominator both EVEN and EQUAL, so as x tends unbounded in either direction, f approaches 1. Horizontal asymptote y=1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Try polynomial long division. You will find 1 plus some rational expression, consistant with what is found as the horizontal asymptote. NO oblique asymptote! \n" ); document.write( " |