document.write( "Question 1028130: \"+log+%28%282x%2B1%29%29=1-log%28%28x-1%29%29+\" \n" ); document.write( "
Algebra.Com's Answer #643284 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
\"log%28%282x%2B1%29%29%2Blog%28%28x-1%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%28%282x%2B1%29%28x-1%29%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "Solution depends on the logarithm base.\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E1=%282x%2B1%29%28x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%2B1%29%28x-1%29=b\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2-x-1-b=0\"
\n" ); document.write( "You can use general quadratic formula solution to have x in terms of b.
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