document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028085>Question 1028085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me factor completely\r<BR>\n" );
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document.write( "2x^3 - 2x^2-12X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643267 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643267\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from<BR>\n" );
document.write( "2x^3 - 2x^2 - 12x = <BR>\n" );
document.write( "let's look for the greatest common factor first (we always do that first)...<BR>\n" );
document.write( "2x(x^2 - x - 6) =<BR>\n" );
document.write( "now factor into binomials...factors of 6 that have a difference of 1...3 and 2...so we get<BR>\n" );
document.write( "2x(x - 3)(x + 2) </SPAN>\n" );
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