document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028068>Question 1028068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The line y = kx +b passes through points A (–1, 3) and B (2, –1). Write the equation of the line. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643260 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Couple of ways to do this...let's find the slope first...<BR>\n" );
document.write( "k (or m) = (3 - (-1))/(-1 - 2) = -4/3<BR>\n" );
document.write( "Now plug into y = kx + b to find b...<BR>\n" );
document.write( "3 = (-4/3)(-1) + b<BR>\n" );
document.write( "3 = 4/3 + b<BR>\n" );
document.write( "b = 5/3<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "y = (-4/3)x + 5/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );