document.write( "Question 1027978: At a local gravel yard, a large skip loader can move a large pile of gravel in 15 minutes. A smaller skip loader can move the same pile of gravel in 2.25 hours. How many minutes would it take the two skip loaders working together to move the gravel pile? \r
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\n" ); document.write( "\n" ); document.write( "It would take about_______for the two skip loaders working together to move the gravel pile. \n" ); document.write( "
Algebra.Com's Answer #643246 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Rate unit should be PILES per HOUR or as PILE per HOURS.\r
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\n" ); document.write( "\n" ); document.write( "\"0.25%2Ahour=15%2Aminutes=%281%2F4%29%2Ahour\"\r
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document.write( "Which Skip Loader    RATE, PILES per HOURS\r\n" );
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document.write( "Large loader,        1/(1/4)=4\r\n" );
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document.write( "Small loader,        1/(2&1/4)=1/(9/4)=4/9
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\n" ); document.write( "\n" ); document.write( "Combined rate for both loaders working together is \"4%2B4%2F9\"
\n" ); document.write( "\"36%2F9%2B4%2F9\"
\n" ); document.write( "\"40%2F9\"
\n" ); document.write( "but if you want TIME for loading or moving 1 whole pile, then \"%289%2F40%29%28hours%2Fpile%29\";
\n" ); document.write( "\"%289%2F40%29%2Ahour%2A60%28minutes%2Fhour%29\"
\n" ); document.write( "\"9%2A6%2F4\"
\n" ); document.write( "\"9%2A3%2F2\"
\n" ); document.write( "\"27%2F2\"
\n" ); document.write( "\"highlight%28%2813%261%2F2%29%2AMINUTES%29\" \n" ); document.write( "
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