document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1027732>Question 1027732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jack deposited $2,000 at 2.75% interest, compounded continuously when he was 18 years old. How much will be in the account when he is 40 years old if he made no other deposits or withdrawals? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #643230 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=643230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Continuous compound interest is found by<BR>\n" );
document.write( "A = Pe^rt so that<BR>\n" );
document.write( "A = (2000)e^(.0275 * 22)<BR>\n" );
document.write( "A = $3662.50 </SPAN>\n" );
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