document.write( "Question 88466: one number is 12 more than another the sum of the smaller number and twice the larger number is 39 find the larger number let x be the larger number and y be the smaller number \n" ); document.write( "

Algebra.Com's Answer #64322 by SandySharma(35) $\"\"$ $\"About$

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let x be the larger number and y be the smaller number.\r
\n" ); document.write( "\n" ); document.write( "one number is 12 more than another \r
\n" ); document.write( "\n" ); document.write( "x = y + 12\r
\n" ); document.write( "\n" ); document.write( "The sum of the smaller number and twice the larger number is 39.\r
\n" ); document.write( "\n" ); document.write( "y + 2x = 39\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Substitute x in this equation\r
\n" ); document.write( "\n" ); document.write( "y + 2 (y +12) = 39\r
\n" ); document.write( "\n" ); document.write( "y + 2y + 24 = 39\r
\n" ); document.write( "\n" ); document.write( "3y + 24 =39\r
\n" ); document.write( "\n" ); document.write( "Subtract 24 on both sides, you will get\r
\n" ); document.write( "\n" ); document.write( "3y = 39 -24\r
\n" ); document.write( "\n" ); document.write( "3y =15
\n" ); document.write( "Divide by 3, you will get\r
\n" ); document.write( "\n" ); document.write( "y = 5\r
\n" ); document.write( "\n" ); document.write( "x = y + 12 = 5 + 12 = 17\r
\n" ); document.write( "\n" ); document.write( "Smaller Number = 5
\n" ); document.write( "Larger Number = 17 \n" ); document.write( "

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